C 練習實例74

題目：連接兩個鏈表。

程序分析：無。

程序源代碼：

//  Created by www.runoob.com on 15/11/9.
//  Copyright © 2015年 菜鳥教程. All rights reserved.
//

#include <stdlib.h>
#include <stdio.h>
struct list
{
    int data;
    struct list *next;
};
typedef struct list node;
typedef node *link;
link delete_node(link pointer,link tmp)
{
    if (tmp==NULL) /*delete first node*/
        return pointer->next;
    else
    {
        if(tmp->next->next==NULL)/*delete last node*/
            tmp->next=NULL;
        else /*delete the other node*/
            tmp->next=tmp->next->next;
    return pointer;
    }
}
void selection_sort(link pointer,int num)
{
    link tmp,btmp;
    int i,min;
    for(i=0;i<num;i++)
    {
        tmp=pointer;
        min=tmp->data;
        btmp=NULL;
        while(tmp->next)
        {
            if(min>tmp->next->data)
            {
                min=tmp->next->data;
                btmp=tmp;
            }
            tmp=tmp->next;
        }
        printf("\40: %d\n",min);
        pointer=delete_node(pointer,btmp);
    }
}
link create_list(int array[],int num)
{
    link tmp1,tmp2,pointer;
    int i;
    pointer=(link)malloc(sizeof(node));
    pointer->data=array[0];
    tmp1=pointer;
    for(i=1;i<num;i++)
    {
        tmp2=(link)malloc(sizeof(node));
        tmp2->next=NULL;
        tmp2->data=array[i];
        tmp1->next=tmp2;
        tmp1=tmp1->next;
    }
    return pointer;
}
link concatenate(link pointer1,link pointer2)
{
    link tmp;
    tmp=pointer1;
    while(tmp->next)
        tmp=tmp->next;
    tmp->next=pointer2;
    return pointer1;
}
void main(void)
{
    int arr1[]={3,12,8,9,11};
    link ptr;
    ptr=create_list(arr1,5);
    selection_sort(ptr,5);
}