題目:Given amxnmatrix, if an element is 0, set its entire row and column to 0. Do it in place.
Follow up:Did you use extra space?
A straight forward solution using O(mn) space is probably a bad idea.
A simple improvement uses O(m+n) space, but still not the best solution.
Could you devise a constant space solution?
解題思路:保存行和列為0的索引,改變該行和該列上的所有數為0即可,實現代碼如下所示:
public class Solution { public void setZeroes(int[][] matrix) { int m=matrix.length; //行數 if(m==0) return ; int n=matrix[0].length; //列數 Lista=new ArrayList (); //存放所有的行中值為0的索引 List b=new ArrayList (); //存放所有的列中值為0的索引 for (int i = 0; i < m; i++) { for (int j = 0; j < n; j++) { if(matrix[i][j]==0) { a.add(i); b.add(j); } } } //將所有行上值為0的那一行的值都改為0 for(int i:a) { for(int j=0;j