上篇博客對右值、右值引用都做了簡要介紹。
我們也要時刻清醒,有時候右值會轉為左值,左值會轉為右值。
(也許“轉換”二字用的不是很准確)
如果我們要避免這種轉換呢?
我們需要一種方法能按照參數原來的類型轉發到另一個函數中,這才完美,我們稱之為完美轉發。
std::forward就可以保存參數的左值或右值特性。
因為是這樣描述的:
When used according to the following recipe in a function template, forwards the argument to another function with the value category it had when passed to the calling function.
例子:
template
void wrapper(T&& arg)
{
foo(std::forward(arg)); // Forward a single argument.
}
If a call to wrapper() passes an rvalue std::string, then T is deduced to std::string (not std::string&, const std::string&, or std::string&&), and std::forward ensures that an rvalue reference is passed to foo.
If a call to wrapper() passes a const lvalue std::string, then T is deduced to const std::string&, and std::forward ensures that a const lvalue reference is passed to foo.
If a call to wrapper() passes a non-const lvalue std::string, then T is deduced to std::string&, and std::forward ensures that a non-const lvalue reference is passed to foo.
看一段網站上的代碼(http://en.cppreference.com/w/cpp/utility/forward):
#include
#include
#include
#include
struct A {
A(int&& n) { std::cout << "rvalue overload, n=" << n << "\n"; }
A(int& n) { std::cout << "lvalue overload, n=" << n << "\n"; }
};
class B {
public:
template
B(T1&& t1, T2&& t2, T3&& t3) :
a1_{std::forward(t1)},
a2_{std::forward(t2)},
a3_{std::forward(t3)}
{
}
private:
A a1_, a2_, a3_;
};
template
std::unique_ptr make_unique1(U&& u)
{
return std::unique_ptr(new T(std::forward(u)));
}
template
std::unique_ptr make_unique(U&&... u)
{
return std::unique_ptr(new T(std::forward(u)...));
}
int main()
{
auto p1 = make_unique1(2); // rvalue
int i = 1;
auto p2 = make_unique1(i); // lvalue
std::cout << "B\n";
auto t = make_unique(2, i, 3);
}
//輸出:
rvalue overload, n=2
lvalue overload, n=1
B
rvalue overload, n=2
lvalue overload, n=1
rvalue overload, n=3
最後,記住:
不管是T&&、左值引用、右值引用,std::forward都會按照原來的類型完美轉發。