(LeetCode OJ) Same Tree【100】

(LeetCode OJ) Same Tree【100】

100. Same Tree

Given two binary trees, write a function to check if they are equal or not.

Two binary trees are considered equal if they are structurally identical and the nodes have the same value.

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樸素的遞歸思想：

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
 //思路首先：只要p和q都不為null且val相等就繼續判斷p的左子樹和q的左子樹以及p的右子樹和q的右子樹
 //如果出現某子樹存在而另一顆樹的相應子樹卻不存在，則返回false
class Solution {
public:
    bool isSameTree(TreeNode* p, TreeNode* q) {
        if(p==NULL&&q==NULL)  
            return true;  
        else if(p==NULL&&q!=NULL)  
            return false;  
        else if(p!=NULL&&q==NULL)  
            return false;  
        else if(p!=NULL&&q!=NULL && p->val!=q->val)  
            return false;  
        else  
            return (isSameTree(p->left,q->left))&&(isSameTree(p->right,q->right));  
    }
};