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 程式師世界 >> 編程語言 >> C語言 >> C++ >> C++入門知識 >> 1031. Hello World for U (20)[字符串處理]——PAT (Advanced Level) Practise

1031. Hello World for U (20)[字符串處理]——PAT (Advanced Level) Practise

編輯:C++入門知識

1031. Hello World for U (20)[字符串處理]——PAT (Advanced Level) Practise


題目信息

1031. Hello World for U (20)

時間限制400 ms
內存限制65536 kB
代碼長度限制16000 B

Given any string of N (>=5) characters, you are asked to form the characters into the shape of U. For example, “helloworld” can be printed as:

h  d
e  l
l  r
lowo

That is, the characters must be printed in the original order, starting top-down from the left vertical line with n1 characters, then left to right along the bottom line with n2 characters, and finally bottom-up along the vertical line with n3 characters. And more, we would like U to be as squared as possible – that is, it must be satisfied that n1 = n3 = max { k| k <= n2 for all 3 <= n2 <= N } with n1 + n2 + n3 - 2 = N.
Input Specification:

Each input file contains one test case. Each case contains one string with no less than 5 and no more than 80 characters in a line. The string contains no white space.

Output Specification:

For each test case, print the input string in the shape of U as specified in the description.

Sample Input:
helloworld!
Sample Output:

h   !
e   d
l   l
lowor

解題思路

字符串操作

AC代碼

#include 
#include 
int main()
{
    char s[100];
    scanf("%s", s);
    int len = strlen(s);
    int tl = (len + 2) / 3 - 1;
    int sp = len - tl * 2 - 2;
    int i = 0;
    for (i = 0; i < tl; ++i){
        putchar(s[i]);
        int t = sp;
        while (t-- > 0) putchar(' ');
        putchar(s[len - 1 - i]);
        putchar('\n');
    }
    for (;i < len - tl; ++i) putchar(s[i]);
    putchar('\n');
    return 0;
}

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