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 程式師世界 >> 編程語言 >> C語言 >> C++ >> C++入門知識 >> LeetCode -- Repeated DNA Sequences

LeetCode -- Repeated DNA Sequences

編輯:C++入門知識

LeetCode -- Repeated DNA Sequences


題目描述:


All DNA is composed of a series of nucleotides abbreviated as A, C, G, and T, for example: ACGAATTCCG. When studying DNA, it is sometimes useful to identify repeated sequences within the DNA.


Write a function to find all the 10-letter-long sequences (substrings) that occur more than once in a DNA molecule.


For example,


Given s = AAAAACCCCCAAAAACCCCCCAAAAAGGGTTT,


Return:
[AAAAACCCCC, CCCCCAAAAA].




就是在一個字符串s中長度為10的字串中找到出現次數大於1次的子串。


思路:
使用哈希統計s[i...i+10]出現的次數,i∈[0,n-9)。




實現代碼:

public class Solution {
    public IList FindRepeatedDnaSequences(string s) 
    {
        if(s.Length < 11){
    		return new List();
    	}
    	var hash = new Dictionary();
    	for(var i = 0;i < s.Length - 9; i++){
    		var t = s.Substring(i,10);
    		if(!hash.ContainsKey(t)){
    			hash.Add(t,1);
    		}
    		else{
    			hash[t]++;
    		}
    	}
    	
    	var ret = new List();
    	foreach(var k in hash.Keys){
    		if(hash[k] > 1){
    			ret.Add(k);
    		}
    	}
    	
    	return ret;
    }
}


 

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