LeetCode -- Validate Binary Search Tree
題目描述:
Given a binary tree, determine if it is a valid binary search tree (BST).
Assume a BST is defined as follows:
The left subtree of a node contains only nodes with keys less than the node's key.
The right subtree of a node contains only nodes with keys greater than the node's key.
Both the left and right subtrees must also be binary search trees.
就是判斷一個二叉樹是否為搜索二叉樹。
搜索二叉樹的定義為,左子樹的每個節點都小於當前節點;右子樹的每個節點都大於當前節點。
思路:中序遍歷節點存入數組,再判斷數組是否為遞增(不包括相等)。
實現代碼:
/**
* Definition for a binary tree node.
* public class TreeNode {
* public int val;
* public TreeNode left;
* public TreeNode right;
* public TreeNode(int x) { val = x; }
* }
*/
public class Solution {
public bool IsValidBST(TreeNode root)
{
var result = new List();
Travel(root, ref result);
for(var i = 0;i < result.Count - 1; i++){
if(result[i+1] <= result[i]){
return false;
}
}
return true;
}
private void Travel(TreeNode node ,ref List result)
{
if(node == null){
return;
}
Travel(node.left, ref result);
result.Add(node.val);
Travel(node.right, ref result);
}
}