All DNA is composed of a series of nucleotides abbreviated as A, C, G, and T, for example: ACGAATTCCG. When studying DNA, it is sometimes useful to identify repeated sequences within the DNA.
Write a function to find all the 10-letter-long sequences (substrings) that occur more than once in a DNA molecule.
For example,
Given s = AAAAACCCCCAAAAACCCCCCAAAAAGGGTTT, Return: [AAAAACCCCC, CCCCCAAAAA].解題報告:標准字符轉二進制的hash table。直接用string進行存儲會內存超時。
采用( s[i] - 'A' + 1 ) % 5 )把A,C,G,T,轉換為1,3,2,0;t = ( (t<<2) & 0xfffff) | ( ( s[i] - 'A' + 1 ) % 5 );進行20位的存貯。
class Solution { public: vectorfindRepeatedDnaSequences(string s) { vector result; unordered_map str; unordered_map ::iterator it; int t; for (int i = 0; i < s.size() ;i++) { t = ( (t<<2) & 0xfffff) | ( ( s[i] - 'A' + 1 ) % 5 ); if (i < 9) continue; it = str.find(t); if (it == str.end()) str[t] = 1; else { if (str[t] == 1) { str[t] = 2; result.push_back(s.substr(i-9,10)); } } } return result; } };