題目:
Given a binary tree, return the postorder traversal of its nodes' values.
For example:
Given binary tree {1,#,2,3}
,
1 2 / 3
return [3,2,1]
.
Note: Recursive solution is trivial, could you do it iteratively?
解題思路:基礎的後序遍歷
/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * };www.Bkjia.com */ class Solution { private: vectors; public: vector postorderTraversal(TreeNode *root) { postOrder(root); return s; } void postOrder(TreeNode *root) { if (root == NULL) return; postOrder(root->left); postOrder(root->right); s.push_back(root->val); } };