There are N gas stations along a circular route, where the amount of gas at station i is gas[i]
.
You have a car with an unlimited gas tank and it costs cost[i]
of gas to travel from station i to its next station (i+1). You begin the journey with an empty tank at one of the gas stations.
Return the starting gas station's index if you can travel around the circuit once, otherwise return -1.
Note:
The solution is guaranteed to be unique.
貪心法 如果此前一段的和小於零,則從以下一個加油站為起點,最後判斷加的氣是否大於用掉的氣,思路參照leetcodee題解
public class Solution { public int canCompleteCircuit(int[] gas, int[] cost) { int all = 0; int sum = 0; int res = -1; for(int i = 0;i=0){ sum +=gas[i]-cost[i]; }else{ sum = 0; res =i; } } return all>=0?(res+1):-1; } }