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 程式師世界 >> 編程語言 >> C語言 >> C++ >> C++入門知識 >> [LeetCode]Gas Station

[LeetCode]Gas Station

編輯:C++入門知識

[LeetCode]Gas Station


 

There are N gas stations along a circular route, where the amount of gas at station i is gas[i].

You have a car with an unlimited gas tank and it costs cost[i] of gas to travel from station i to its next station (i+1). You begin the journey with an empty tank at one of the gas stations.

Return the starting gas station's index if you can travel around the circuit once, otherwise return -1.

Note:
The solution is guaranteed to be unique.

貪心法 如果此前一段的和小於零,則從以下一個加油站為起點,最後判斷加的氣是否大於用掉的氣,思路參照leetcodee題解

 

 

public class Solution {
    public int canCompleteCircuit(int[] gas, int[] cost) {
    	int all = 0;
    	int sum = 0;
    	int res = -1;
    	for(int i = 0;i=0){
    			sum +=gas[i]-cost[i];
    		}else{
    			sum = 0;
    			res =i;
    		}
    	}
    	return all>=0?(res+1):-1;
    }
}


 

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