POJ 2299 Ultra-QuickSort £¨¹é²¢ÅÅÐò£©
Ultra-QuickSort
Time Limit: 7000MS
Memory Limit: 65536K
Total Submissions: 43446
Accepted: 15822
Description

In this problem, you have to analyze a particular sorting algorithm. The algorithm processes a sequence of n distinct integers by swapping two adjacent sequence elements until the sequence is
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The input contains several test cases. Every test case begins with a line that contains a single integer n < 500,000 -- the length of the input sequence. Each of the the following n lines contains a single integer 0 ¡Ü a[i] ¡Ü 999,999,999, the i-th input sequence
element. Input is terminated by a sequence of length n = 0. This sequence must not be processed.
Output
For every input sequence, your program prints a single line containing an integer number op, the minimum number of swap operations necessary to sort the given input sequence.
Sample Input
5
9
1
0
5
4
3
1
2
3
0
Sample Output
6
0
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#include
#include
#define M 500010
int a[M];
int aux[M];
long long int ans;
using namespace std;
void merge(int a[],int l,int mid,int h)
{
for(int k=l;k<=h;++k)
aux[k]=a[k];
int i=l;
int j=mid+1;
for(int k=l;k<=h;++k)
{
if(i>mid)a[k]=aux[j++];
else if(j>h)a[k]=aux[i++];
else if(aux[i]=h)return ;
int mid=l+(h-l)/2;
sort(a,l,mid);
sort(a,mid+1,h);
merge(a,l,mid,h);
}
int main(int argc, char *argv[])
{
//freopen("2299.in","r",stdin);
int n;
while(scanf("%d",&n)&&n!=0){
ans=0;
for(int i=0;i