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 程式師世界 >> 編程語言 >> C語言 >> C++ >> C++入門知識 >> 158A - Next Round

158A - Next Round

編輯:C++入門知識

158A - Next Round


A. Next Round time limit per test 3 seconds memory limit per test 256 megabytes input standard input output standard output

"Contestant who earns a score equal to or greater than the k-th place finisher's score will advance to the next round, as long as the contestant earns a positive score..." — an excerpt from contest rules.

A total of n participants took part in the contest (n?≥?k), and you already know their scores. Calculate how many participants will advance to the next round.

Input

The first line of the input contains two integers n and k (1?≤?k?≤?n?≤?50) separated by a single space.

The second line contains n space-separated integers a1,?a2,?...,?an (0?≤?ai?≤?100), where ai is the score earned by the participant who got the i-th place. The given sequence is non-increasing (that is, for all i from 1 to n?-?1 the following condition is fulfilled: ai?≥?ai?+?1).

Output

Output the number of participants who advance to the next round.

Sample test(s) input
8 5
10 9 8 7 7 7 5 5
output
6
input
4 2
0 0 0 0
output
0
Note

In the first example the participant on the 5th place earned 7 points. As the participant on the 6th place also earned 7 points, there are 6 advancers.

In the second example nobody got a positive score.

import java.util.*;


public class Main {
    public static void main(String[] args) {
        
        Scanner sc=new Scanner(System.in);
        
            int n=sc.nextInt();
            int k=sc.nextInt();
            int count=0;
        int[] score = new int[60];
            for(int i=0;i=max&&score[i]>0)
                    count++;
            System.out.println(count);
    }
}


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