Given two binary strings, return their sum (also a binary string).
For example,
a = "11"
b = "1"
Return "100".
我的C++實現代碼如下:
string addBinary(string a, string b) { string sum; int carry = 0; for (int i = a.size() - 1, j = b.size() - 1; i >= 0 || j >= 0; --i, --j) { string bitAdd("0"); int src1 = (i >= 0 ? a[i] - '0' : 0); int src2 = (j >= 0 ? b[j] - '0' : 0); bitAdd[0] += (src1 + src2 + carry) & 1; carry = ((src1 + src2 + carry) & 2) ? 1 : 0; sum = bitAdd + sum; } if (carry) { string s("1"); sum = s + sum; } return sum; }