Codeforces Round #277.5 (Div. 2)(C題)

Codeforces Round #277.5 (Div. 2)(C題)

C. Given Length and Sum of Digits... time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output

You have a positive integer m and a non-negative integer s. Your task is to find the smallest and the largest of the numbers that have length m and sum of digits s. The required numbers should be non-negative integers written in the decimal base without leading zeroes.

Input

The single line of the input contains a pair of integers m, s (1?≤?m?≤?100,?0?≤?s?≤?900) — the length and the sum of the digits of the required numbers.

Output

In the output print the pair of the required non-negative integer numbers — first the minimum possible number, then — the maximum possible number. If no numbers satisfying conditions required exist, print the pair of numbers "-1 -1" (without the quotes).

Sample test(s) input

2 15

output

69 96

input

3 0

output

-1 -1

#include 
#include 
#include 
using namespace std;

bool can(int m, int s)
{
    if(s >= 0 && 9*m >= s) return true;
    else return false;
}
int main()
{
    int m,s;
    cin>>m>>s;
    if(!can(m,s))
    {
        cout<<"-1"<<" "<<"-1"<= 10)
        {
            cout<<"-1"<<" "<<"-1"< 0 || (j == 0 && i > 1) ) && can(m - i, sum - j))
                   {
                       minn += char('0' + j);
                       sum -= j;
                       break;
                   }
            }



            sum = s;
               for(int i = 1; i <= m; i++)
                for(int j = 9; j >= 0; j--)
            {
                if(can(m - i, sum - j))
                   {
                       maxn += char('0' + j);
                       sum -= j;
                       break;
                   }
            }

            cout<