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 程式師世界 >> 編程語言 >> C語言 >> C++ >> C++入門知識 >> POJ 1579-Function Run Fun(記憶化搜索)

POJ 1579-Function Run Fun(記憶化搜索)

編輯:C++入門知識

POJ 1579-Function Run Fun(記憶化搜索)


Function Run Fun Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 16503   Accepted: 8514

Description

We all love recursion! Don't we?

Consider a three-parameter recursive function w(a, b, c):

if a <= 0 or b <= 0 or c <= 0, then w(a, b, c) returns:
1

if a > 20 or b > 20 or c > 20, then w(a, b, c) returns:
w(20, 20, 20)

if a < b and b < c, then w(a, b, c) returns:
w(a, b, c-1) + w(a, b-1, c-1) - w(a, b-1, c)

otherwise it returns:
w(a-1, b, c) + w(a-1, b-1, c) + w(a-1, b, c-1) - w(a-1, b-1, c-1)

This is an easy function to implement. The problem is, if implemented directly, for moderate values of a, b and c (for example, a = 15, b = 15, c = 15), the program takes hours to run because of the massive recursion.

Input

The input for your program will be a series of integer triples, one per line, until the end-of-file flag of -1 -1 -1. Using the above technique, you are to calculate w(a, b, c) efficiently and print the result.

Output

Print the value for w(a,b,c) for each triple.

Sample Input

1 1 1
2 2 2
10 4 6
50 50 50
-1 7 18
-1 -1 -1

Sample Output

w(1, 1, 1) = 2
w(2, 2, 2) = 4
w(10, 4, 6) = 523
w(50, 50, 50) = 1048576
w(-1, 7, 18) = 1
巨水。。
一開始wa了一組數據 (0,21,21)

#include  #include  #include  #include  #include  #include  #include  #include  #include  #include  #include  #include#include  #define ll long long #define maxn 116 #define pp pair #define INF 0x3f3f3f3f #define max(x,y) ( ((x) > (y)) ? (x) : (y) ) #define min(x,y) ( ((x) > (y)) ? (y) : (x) ) using namespace std; int n,m,dp[22][22][22]; int dfs(int x,int y,int z) { if(x<=0||y<=0||z<=0) return 1; if(x>20||y>20||z>20) return dfs(20,20,20); if(dp[x][y][z]!=INF) return dp[x][y][z]; dp[x][y][z]=0; if(x<y&&y<z) dp[x][y][z]+="(dfs(x,y,z-1)+dfs(x,y-1,z-1)-dfs(x,y-1,z));" else="" return="" dp[x][y][z];="" }="" int="" main()="" {="" a,b,c;="" while(scanf("%d%d%d",&a,&b,&c))="" if(a="=-1&&b==-1&&c==-1)break;" memset(dp,inf,sizeof(dp));="" printf("w(%d,="" %d,="" %d)="%d\n&quot;,a,b,c,dfs(a,b,c));" 0;="" }

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