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 程式師世界 >> 編程語言 >> C語言 >> C++ >> C++入門知識 >> 函數可以連接任意兩個filter

函數可以連接任意兩個filter

編輯:C++入門知識

函數可以連接任意兩個filter


函數可以連接任意兩個filter

HRESULT ConnectFilters( IBaseFilter *pSrc, IBaseFilter *pDest )
{
	IPin *pIn = 0;
	IPin *pOut = 0;
	IEnumPins *pOutEnum;
	IEnumPins *pInEnum;
	PIN_DIRECTION ThisPinDir;
	
	HRESULT hr = pSrc->EnumPins( &pOutEnum );
	hr = pDest->EnumPins( &pInEnum );
	while (pOutEnum->Next( 1, &pOut, NULL) == S_OK )
	{
		hr = pOut->QueryDirection( &ThisPinDir );
		while( ThisPinDir==PINDIR_OUTPUT && pInEnum->Next( 1, &pIn, 0 ) == S_OK )
		{
			hr = pIn->QueryDirection( &ThisPinDir );
			if( ThisPinDir==PINDIR_INPUT )
			{
				// Try to connect them.
				hr = pigb->Connect( pOut, pIn);
				if(SUCCEEDED(hr))
				{
					hr = pOutEnum->Release();
					hr = pInEnum->Release();
					hr = pIn->Release();
					hr = pOut->Release();
					return S_OK;
				}
				
			}
			hr = pIn->Release();
		}//end while
		
		hr = pInEnum->Reset();
		hr = pOut->Release();
    }//end while
	pOutEnum->Reset();
	hr = pOutEnum->Release();
	hr = pInEnum->Release();
	
    return E_FAIL;
}


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