hdu 5077 NAND(暴力打表)

hdu 5077 NAND(暴力打表)

題目鏈接：hdu 5077 NAND

題目大意：Xiaoqiang要寫一個編碼程序，然後根據x1，x2，x3的值構造出8個字符，現在給定要求生成的8個字符，問

說Xiaoqiang最少要寫多少行代碼。代碼內容只能為NAND操作和return操作，操作的變量可以是常數。

解題思路：輸入總共就256中情況，所以暴力剪枝打表，打表的代碼手賤給刪了。。。所以就將一下思路，開一個s數組

表示變量，然後對應每一層每次兩個變量進行NAND操作。

大致三個剪枝，dfs時候，變量出現相同就跳過；8個字符可以直接根據數的位運算計算；單前層出現相同的跳過。

#include 
#include 
#include 

using namespace std;

const int ans[300] = {1, 5, 6, 3, 6, 3, 7, 4, 7, 8, 4, 5, 4, 5, 4, 1, 6, 3, 7, 4, 7, 4, 9, 7, 8, 8, 7, 5, 7, 5, 7, 4, 7, 8, 4, 5, 8, 8, 7, 5, 8, 9, 5, 6, 8, 8, 5, 5, 4, 5, 4, 1, 7, 5, 7, 4, 8, 8, 5, 5, 5, 7, 6, 4, 7, 8, 8, 8, 4, 5, 7, 5, 8, 9, 8, 8, 5, 6, 5, 5, 4, 5, 7, 5, 4, 1, 7, 4, 8, 8, 5, 7, 5, 5, 6, 4, 8, 9, 8, 8, 8, 8, 5, 7, 11, 9, 8, 9, 8, 9, 8, 8, 5, 6, 5, 5, 5, 5, 6, 4, 8, 9, 8, 8, 8, 8, 8, 7, 8, 9, 9, 9, 9, 9, 10, 9, 5, 7, 6, 6, 6, 6, 7, 6, 9, 9, 10, 9, 10, 9, 10, 10, 7, 6, 7, 7, 7, 7, 9, 7, 5, 7, 6, 6, 7, 6, 7, 7, 5, 6, 2, 3, 6, 6, 4, 3, 6, 6, 7, 6, 7, 7, 9, 7, 6, 6, 4, 3, 7, 7, 7, 6, 5, 7, 7, 6, 6, 6, 7, 7, 5, 6, 6, 6, 2, 3, 4, 3, 6, 6, 7, 7, 7, 6, 9, 7, 6, 6, 7, 7, 4, 3, 7, 6, 5, 6, 6, 6, 6, 6, 7, 7, 8, 9, 5, 6, 5, 6, 2, 5, 2, 3, 4, 3, 4, 3, 7, 6, 5, 6, 2, 5, 2, 5, 4, 1};

int main () {
    int cas;
    char p[10];
    scanf("%d", &cas);
    while (cas--) {
        scanf("%s", p);
        int ret = 0;
        for (int i = 0; i < 8; i++)
            ret = ret * 2 + p[i] - '0';
        printf("%d\n", ans[ret]);
    }

    return 0;
}