POJ 1496 POJ 1850 組合計數
Code
Time Limit: 1000MS Memory Limit: 30000K
Total Submissions: 8256 Accepted: 3906
Description
Transmitting and memorizing information is a task that requires different coding systems for the best use of the available space. A well known system is that one where a number is associated to a character sequence. It is considered that the words are made
only of small characters of the English alphabet a,b,c, ..., z (26 characters). From all these words we consider only those whose letters are in lexigraphical order (each character is smaller than the next character).
The coding system works like this:
? The words are arranged in the increasing order of their length.
? The words with the same length are arranged in lexicographical order (the order from the dictionary).
? We codify these words by their numbering, starting with a, as follows:
a - 1
b - 2
...
z - 26
ab - 27
...
az - 51
bc - 52
...
vwxyz - 83681
...
Specify for a given word if it can be codified according to this coding system. For the affirmative case specify its code.
Input
The only line contains a word. There are some constraints:
? The word is maximum 10 letters length
? The English alphabet has 26 characters.
Output
The output will contain the code of the given word, or 0 if the word can not be codified.
Sample Input
bf
Sample Output
55
Source
Romania OI 2002
/**************************************
author : Grant Yuan
time : 2014/10/12 17:06
algortihm: 組合計數
source : POJ 1496 POJ 1850
***************************************/
#include
#include
#include
#include
#include
using namespace std;
char a[27];
int num[27][27];
long long ans;
bool check()
{
int l=strlen(a);
if(l==1) return 1;
for(int i=0;i=a[i+1]) return 1;
return 0;
}
void Get_num()
{
int l=strlen(a);
for(int i=0;i<=26;i++)
for(int j=0;j<=i;j++)
{
num[i][j]=0;
if(i==0||j==0) num[i][j]=1;
else num[i][j]=num[i-1][j]+num[i-1][j-1];
}
}
void Get_sum1()
{
int l=strlen(a);
ans=0;
for(int i=0;i
