設50元的人為+1 100元的人為-1 滿足前任意k個人的和大於等於0 卡特蘭數
C(n+m, m)-C(n+m, m+1)*n!*m!
import java.math.*; import java.util.*; public class Main { /** * @param args */ public static void main(String[] args) { Scanner sc = new Scanner(System.in); int cas = 1; while(true){ int m = sc.nextInt(); int n = sc.nextInt(); if(m == 0 && n == 0) break; System.out.println("Test #"+cas+":"); cas++; if(m < n){ System.out.println(0); continue; } BigInteger ans1 = BigInteger.valueOf(1); int x = n+m; for(int i = 1; i <= m; i++){ ans1 = ans1.multiply(BigInteger.valueOf(x)); x--; } for(int i = 1; i <= n; i++){ ans1 = ans1.multiply(BigInteger.valueOf(i)); } BigInteger ans2 = BigInteger.valueOf(1); x = n+m; for(int i = 1; i <= m+1; i++){ ans2 = ans2.multiply(BigInteger.valueOf(x)); x--; ans2 = ans2.divide(BigInteger.valueOf(i)); } for(int i = 1; i <= n; i++){ ans2 = ans2.multiply(BigInteger.valueOf(i)); } for(int i = 1; i <= m; i++){ ans2 = ans2.multiply(BigInteger.valueOf(i)); } System.out.println(ans1.subtract(ans2)); } } }