Given an unsorted array of integers, find the length of the longest consecutive elements sequence.
For example,
Given [100, 4, 200, 1, 3, 2]
,
The longest consecutive elements sequence is [1, 2, 3, 4]
. Return its
length: 4
.
Your algorithm should run in O(n) complexity.
class Solution { public: int longestConsecutive(std::vector&num) { std::unordered_set a; std::unordered_set b; for (int i = 0; i < num.size(); i++) { a.insert(num[i]); } int max = 0; for (int i = 0; i < num.size(); i++) { if(b.find(num[i]) != b.end()) continue; int cnt = 1,n = num[i],m = num[i]; while(a.find(--n) != a.end()) b.insert(n),cnt++; while(a.find(++m) != a.end()) b.insert(m),cnt++; max = max > cnt ? max : cnt; } return max; } };