STL algorithm算法any_of譯文及使用（3）

 

std::any_of

template 
  bool any_of (InputIterator first, InputIterator last, UnaryPredicate pred);

Test if any element in range fulfills condition Returns true if pred returns true for any of the elements in the range [first,last), and false otherwise.

如果范圍內任一元素使pred返回true,則返回true,否則返回false.

例子：

 

#include 
#include 
using namespace std;
bool isGreat(int i){
	if(i>=5){
		cout<=5<< ,match!< vi{0,1,2,3,4,5,6};
	if(any_of(vi.begin(),vi.end(),isGreat))
		cout<=5 <=1 <運行截圖：
 
If [first,last) is an empty range, the function returns false.
如果范圍為空，則返回false.(因為沒有任一匹配)
例子：
 
#include 
#include 
using namespace std;
bool isGreat(int i){
	if(i>=5){
		cout<=5<< ,match!< vi{0,1,2,3,4,5,6};
	if(any_of(vi.begin(),vi.begin(),isGreat))
		cout<
 
The behavior of this function template is equivalent to: