Codeforce 264 B Caisa and Pylons(模擬)

Codeforce 264 B Caisa and Pylons(模擬)

題意 Caisa走台階 有n個台階 第i個台階的高度為h[i] 從第i個台階包括地面到下一個台階得到的能量為h[i]-h[i+1] 能量不足以跳到下一個台階就要補充能量 求Caisa跳完所有台階最少要補充多少能量

水題 直接模擬

#include
#include
using namespace std;
const int N = 100005;
int h[N];
int main()
{
    int n, e, ans;
    scanf("%d",&n);
    for (int i = 1; i <= n; ++i)
        scanf ("%d", &h[i]);
    ans = 0;
    for (int i = e = 0; i < n; ++i)
    {
        if (h[i] + e < h[i + 1])
        {
            int t = (h[i + 1] - e - h[i]);
            h[i] += t;
            ans += t;
        }
        e += (h[i] - h[i + 1]);
    }
    printf ("%d\n", ans);
    return 0;
}

Caisa solved the problem with the sugar and now he is on the way back to home.

Caisa is playing a mobile game during his path. There are (n?+?1) pylons numbered from 0 to n in this game. The pylon with number 0 has zero height, the pylon with number i (i?>?0) has height h_i. The goal of the game is to reach n-th pylon, and the only move the player can do is to jump from the current pylon (let's denote its number as k) to the next one (its number will be k?+?1). When the player have made such a move, its energy increases by h_k?-?h_k?+?1 (if this value is negative the player loses energy). The player must have non-negative amount of energy at any moment of the time.

Initially Caisa stand at 0 pylon and has 0 energy. The game provides a special opportunity: one can pay a single dollar and increase the height of anyone pylon by one. Caisa may use that opportunity several times, but he doesn't want to spend too much money. What is the minimal amount of money he must paid to reach the goal of the game?

The first line contains integer n (1?≤?n?≤?10⁵). The next line contains n integers h₁, h₂,?..., h_n (1??≤??h_i??≤??10⁵) representing the heights of the pylons.

Print a single number representing the minimum number of dollars paid by Caisa.

5
3 4 3 2 4

4

3
4 4 4

4

In the first sample he can pay 4 dollars and increase the height of pylon with number 0 by 4 units. Then he can safely pass to the last pylon.