1148 - Mad Counting
PDF (English) Statistics Forum
Time Limit: 0.5 second(s) Memory Limit: 32 MB
Mob was hijacked by the mayor of the Town "TruthTown". Mayor wants Mob to count the total population of the town. Now the naive approach to this problem will be counting people one by one. But as we all know Mob is a bit lazy, so he is finding some other approach
so that the time will be minimized. Suddenly he found a poll result of that town where N people were asked "How many people in this town other than yourself support the same team as you in the FIFA world CUP 2010?" Now Mob wants to know if he can find the
minimum possible population of the town from this statistics. Note that no people were asked the question more than once.
Input
Input starts with an integer T (≤ 100), denoting the number of test cases.
Each case starts with an integer N (1 ≤ N ≤ 50). The next line will contain N integers denoting the replies (0 to 106) of the people.
Output
For each case, print the case number and the minimum possible population of the town.
Sample Input
Output for Sample Input
2
4
1 1 2 2
1
0
Case 1: 5
Case 2: 1
PROBLEM SETTER: MUHAMMAD RIFAYAT SAMEE
SPECIAL THANKS: JANE ALAM JAN
思路：
把每個人說的數和說這個數的人數分別存在了兩個數組中，然後用每個數除以這個數被說的次數向上取整累計加和即可；
/***********************************
author : Grant Yuan
time : 2014/8/21 10:22
algorithm: Basic Math
source : LightOj 1148
************************************/
#include
using namespace std;
int a[57];
int f[57];
int main()
{
int t,n,ans,sum;
scanf("%d",&t);
for(int i=1;i<=t;i++)
{
memset(a,0,sizeof(a));
memset(f,0,sizeof(f));
scanf("%d",&n);
ans=0;sum=0;
for(int j=0;j
