Description
A lattice point (x, y) in the first quadrant (x and y are integers greater than or equal to 0), other than the origin, is visible from the origin if the line from (0, 0) to (x, y) does not pass through any other lattice point. For example, the point (4, 2) is not visible since the line from the origin passes through (2, 1). The figure below shows the points (x, y) with 0 ≤ x, y ≤ 5 with lines from the origin to the visible points.
Write a program which, given a value for the size, N, computes the number of visible points (x<喎?http://www.Bkjia.com/kf/ware/vc/" target="_blank" class="keylink">vc3Ryb25nPjwvZW0+LCA8ZW0+PHN0cm9uZz55PC9zdHJvbmc+PC9lbT4pIHdpdGggMCCh3CA8ZW0+PHN0cm9uZz54PC9zdHJvbmc+PC9lbT4sIDxlbT48c3Ryb25nPnk8L3N0cm9uZz48L2VtPiCh3CA8ZW0+PHN0cm9uZz5OPC9zdHJvbmc+PC9lbT4uPC9wPgoKPHAgY2xhc3M9"pst">Input
The first line of input contains a single integer C (1 ≤ C ≤ 1000) which is the number of datasets that follow.
Each dataset consists of a single line of input containing a single integer N (1 ≤ N ≤ 1000), which is the size.
Output
For each dataset, there is to be one line of output consisting of: the dataset number starting at 1, a single space, the size, a single space and the number of visible points for that size.
Sample Input
4 2 4 5 231
Sample Output
1 2 5 2 4 13 3 5 21 4 231 32549
思路：實際上題目在說的時候已經為你提供了思路，那就是比較斜率了。只要是斜率沒有出現的點，那麼我們就可以加上這些點，我們發現，每多一個數，就意味著要多一個外層，我們只需要加上這些外層上的點就可以了，而且一個外層上的點是對稱的！
所以AC代碼：
