數組:
構造二叉樹, 需要使用兩個隊列(queue), 保存子節點和父節點, 並進行交換;
打印二叉樹, 需要使用兩個隊列(queue), 依次打印父節點和子節點, 並進行交換;
二叉樹的數據結構:
struct BinaryTreeNode { int m_nValue; BinaryTreeNode* m_pParent; BinaryTreeNode* m_pLeft; BinaryTreeNode* m_pRight; };
代碼:
/* * main.cpp * * Created on: 2014.6.12 * Author: Spike */ /*eclipse cdt, gcc 4.8.1*/ #include#include #include using namespace std; struct BinaryTreeNode { int m_nValue; BinaryTreeNode* m_pParent; BinaryTreeNode* m_pLeft; BinaryTreeNode* m_pRight; }; void printTree (BinaryTreeNode* tree) { BinaryTreeNode* node = tree; std::queue temp1; std::queue temp2; temp1.push(node); while (!temp1.empty()) { node = temp1.front(); if (node->m_pLeft != NULL) { temp2.push(node->m_pLeft); } if (node->m_pRight != NULL) { temp2.push(node->m_pRight); } temp1.pop(); std::cout << node->m_nValue << ; if (temp1.empty()) { std::cout << std::endl; temp1 = temp2; std::queue empty; std::swap(temp2, empty); } } } BinaryTreeNode* buildTree (const std::vector & L) { if (L.empty()) return nullptr; std::queue parentQueue; std::queue childQueue; BinaryTreeNode* root = new BinaryTreeNode(); root->m_nValue = L[0]; parentQueue.push(root); std::size_t times = 1; while (times < L.size()) { BinaryTreeNode* parent = parentQueue.front(); parentQueue.pop(); BinaryTreeNode* lchild = new BinaryTreeNode(); lchild->m_nValue = L[times]; lchild->m_pLeft = nullptr; lchild->m_pRight = nullptr; ++times; parent->m_pLeft = lchild; lchild->m_pParent = parent; childQueue.push(lchild); if (times == L.size()) break; BinaryTreeNode* rchild = new BinaryTreeNode(); rchild->m_nValue = L[times]; rchild->m_pLeft = nullptr; rchild->m_pRight = nullptr; ++times; parent->m_pRight = rchild; rchild->m_pParent = parent; childQueue.push(rchild); if (parentQueue.empty()) { parentQueue = childQueue; std::queue empty; std::swap(childQueue, empty); } } return root; } int main (void) { std::vector L = {49, 38, 65, 97, 76, 13, 27, 49}; BinaryTreeNode* tree = buildTree(L); printTree(tree); return 0; }
輸出:
49 38 65 97 76 13 27 49