題意:求'X'圍成的周長
思路:按理說每增加一個就是周長加4,但是要減去重復的地方,這裡我是用BFS做的,如果是BFS的模板思路的話是不行的,應該要先取出再標記
#include#include #include #include #include using namespace std; const int MAXN = 30; struct node { int x,y; }; queue qu; int dx[] = {0,0,1,-1,1,1,-1,-1}; int dy[] = {1,-1,0,0,1,-1,1,-1}; int vis[MAXN][MAXN],R,C,sx,sy,ans; char map[MAXN][MAXN]; int check(int x, int y) { if (x >= 0 && x < R && y >= 0 && y < C && map[x][y] == 'X') return 1; return 0; } int bfs(int r, int c) { node st; st.x = r,st.y = c; qu.push(st); while (!qu.empty()) { node cur = qu.front(); qu.pop(); if (!vis[cur.x][cur.y]) { ans += 4; for (int i = 0; i < 4; i++) { int nx = cur.x + dx[i]; int ny = cur.y + dy[i]; if (check(nx, ny) && vis[nx][ny]) ans -= 2; } vis[cur.x][cur.y] = 1; for (int i = 0; i < 8; i++) { int nx = cur.x + dx[i]; int ny = cur.y + dy[i]; if (check(nx, ny)) { st.x = nx; st.y = ny; qu.push(st); } } } } return ans; } int main() { while (scanf("%d%d%d%d%*c", &R, &C, &sx, &sy) != EOF && R+C+sx+sy != 0) { memset(map, 0, sizeof(map)); memset(vis, 0, sizeof(vis)); while (!qu.empty()) qu.pop(); ans = 0; for (int i = 0; i < R; i++) gets(map[i]); printf("%d\n", bfs(sx-1, sy-1)); } return 0; }