點擊打開鏈接 Milk Patterns Time Limit: 5000MS Memory Limit: 65536K Total Submissions: 9361 Accepted: 4218 Case Time Limit: 2000MS
Description
Farmer John has noticed that the quality of milk given by his cows varies from day to day. On further investigation, he discovered that although he can't predict the quality of milk from one day to the next, there are some regular patterns in the daily milk quality.
To perform a rigorous study, he has invented a complex classification scheme by which each milk sample is recorded as an integer between 0 and 1,000,000 inclusive, and has recorded data from a single cow over N (1 ≤ N≤ 20,000) days. He wishes to find the longest pattern of samples which repeats identically at least K (2 ≤ K ≤ N) times. This may include overlapping patterns -- 1 2 3 2 3 2 3 1 repeats 2 3 2 3 twice, for example.
Help Farmer John by finding the longest repeating subsequence in the sequence of samples. It is guaranteed that at least one subsequence is repeated at least K times.
Input
Line 1: Two space-separated integers: N and KOutput
Line 1: One integer, the length of the longest pattern which occurs at least K timesSample Input
8 2 1 2 3 2 3 2 3 1
Sample Output
4
Source
USACO 2006 December Gold 給定一個字符串,求至少出現 k 次的最長重復子串,這 k 個子串可以重疊。//4876K 172MS #include#include #include #define M 20007 #define MAX 1000010 using namespace std; int sa[MAX],rank[MAX],height[MAX]; int wa[MAX],wb[MAX],wv[MAX],ws[MAX]; int num[MAX],s[MAX]; int cmp(int *r,int a,int b,int l) { return r[a]==r[b]&&r[a+l]==r[b+l]; } void get_sa(int *r,int n,int m)//求get函數 { int i,j,p,*x=wa,*y=wb,*t; for(i=0; i =0; i--)sa[--ws[x[i]]]=i; for(j=1,p=1; p =j)y[p++]=sa[i]-j; for(i=0; i =0; i--)sa[--ws[wv[i]]]=y[i]; for(t=x,x=y,y=t,p=1,x[sa[0]]=0,i=1; i