題目
Implement wildcard pattern matching with support for '?'
and '*'
.
'?' Matches any single character. '*' Matches any sequence of characters (including the empty sequence). The matching should cover the entire input string (not partial). The function prototype should be: bool isMatch(const char *s, const char *p) Some examples: isMatch("aa","a") → false isMatch("aa","aa") → true isMatch("aaa","aa") → false isMatch("aa", "*") → true isMatch("aa", "a*") → true isMatch("ab", "?*") → true isMatch("aab", "c*a*b") → false分析
通過率很低的一題,Java沒指針寫起來是不順暢。
貪心的策略,能匹配就一直往後遍歷,匹配不上了就看看前面有沒有'*'來救救場,再從'*'後面接著試。
代碼
public class WildcardMatching { public boolean isMatch(String s, String p) { int i = 0; int j = 0; int star = -1; int mark = -1; while (i < s.length()) { if (j < p.length() && (p.charAt(j) == '?' || p.charAt(j) == s.charAt(i))) { ++i; ++j; } else if (j < p.length() && p.charAt(j) == '*') { star = j++; mark = i; } else if (star != -1) { j = star + 1; i = ++mark; } else { return false; } } while (j < p.length() && p.charAt(j) == '*') { ++j; } return j == p.length(); } }