程序師世界是廣大編程愛好者互助、分享、學習的平台,程序師世界有你更精彩!
首頁
編程語言
C語言|JAVA編程
Python編程
網頁編程
ASP編程|PHP編程
JSP編程
數據庫知識
MYSQL數據庫|SqlServer數據庫
Oracle數據庫|DB2數據庫
 程式師世界 >> 編程語言 >> C語言 >> C++ >> C++入門知識 >> HDOJ 4608 I-number

HDOJ 4608 I-number

編輯:C++入門知識

暴力枚舉。。。

I-number

Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 2803 Accepted Submission(s): 1065


Problem Description The I-number of x is defined to be an integer y, which satisfied the the conditions below:
1. y>x;
2. the sum of each digit of y(under base 10) is the multiple of 10;
3. among all integers that satisfy the two conditions above, y shouble be the minimum.
Given x, you're required to calculate the I-number of x.
Input An integer T(T≤100) will exist in the first line of input, indicating the number of test cases.
The following T lines describe all the queries, each with a positive integer x. The length of x will not exceed 105.

Output Output the I-number of x for each query.
Sample Input
1
202

Sample Output
208

Source 2013 Multi-University Training Contest 1
#include 
#include 
#include 
#include 

using namespace std;

const int maxn=200100;

char str[maxn];

bool ck(char str[])
{
    int r=0;
    int n=strlen(str);
    for(int i=0;i=n) str[i]='0';
        int t=str[i]-'0';
        if(t+c<10)
        {
            str[i]++;
            c=0;
            break;
        }
        else
        {
            str[i]='0'+t+c-10;
            c=1;
        }
    }
    return true;
}

int main()
{
    int T_T;
    scanf("%d",&T_T);
    while(T_T--)
    {
        memset(str,0,sizeof(str));
        scanf("%s",str);
        reverse(str,str+strlen(str));
        while(PlusOne(str)) if(ck(str)) break;
        reverse(str,str+strlen(str));
        printf("%s\n",str);
    }
    return 0;
}




  1. 上一頁:
  2. 下一頁:
Copyright © 程式師世界 All Rights Reserved