UVa 621 秘密研究

/*

* 解題思路：

* 很簡單的一道水題，直接按題目訊息輸出即可

*/

#include 
#include 
int main( )
{
    int t;
    int len;
    char s[ 1000 ];

    scanf("%d",&t);
    while( t-- )
    {
        scanf("%s",s);

        len = strlen( s );
        if( (s[ 0 ] == '1' && len == 1) || (s[ 0 ] == '4' && len == 1 ) || ( s[ 0 ] == '7' && s[ 1 ] == '8' && len == 2 ) )
            printf("+\n");
        else if( s[ len-1 ] == '5' && s[ len-2 ] == '3' )
            printf("-\n");
        else if( s[ 0 ] == '9' && s[ len-1 ] == '4' )
            printf("*\n");
        else if( s[ 0 ] == '1' && s[ 1 ] == '9' && s[ 2 ] == '0' )
            printf("?\n");
    }
    return 0;
}