Hardwood Species Time Limit: 10000MS Memory Limit: 65536K Total Submissions: 14326 Accepted: 5814 Description Hardwoods are the botanical group of trees that have broad leaves, produce a fruit or nut, and generally go dormant in the winter. America's temperate climates produce forests with hundreds of hardwood species -- trees that share certain biological characteristics. Although oak, maple and cherry all are types of hardwood trees, for example, they are different species. Together, all the hardwood species represent 40 percent of the trees in the United States. On the other hand, softwoods, or conifers, from the Latin word meaning "cone-bearing," have needles. Widely available US softwoods include cedar, fir, hemlock, pine, redwood, spruce and cypress. In a home, the softwoods are used primarily as structural lumber such as 2x4s and 2x6s, with some limited decorative applications. Using satellite imaging technology, the Department of Natural Resources has compiled an inventory of every tree standing on a particular day. You are to compute the total fraction of the tree population represented by each species. Input Input to your program consists of a list of the species of every tree observed by the satellite; one tree per line. No species name exceeds 30 characters. There are no more than 10,000 species and no more than 1,000,000 trees. Output Print the name of each species represented in the population, in alphabetical order, followed by the percentage of the population it represents, to 4 decimal places. Sample Input Red Alder Ash Aspen Basswood Ash Beech Yellow Birch Ash Cherry Cottonwood Ash Cypress Red Elm Gum Hackberry White Oak Hickory Pecan Hard Maple White Oak Soft Maple Red Oak Red Oak White Oak Poplan Sassafras Sycamore Black Walnut Willow Sample Output Ash 13.7931 Aspen 3.4483 Basswood 3.4483 Beech 3.4483 Black Walnut 3.4483 Cherry 3.4483 Cottonwood 3.4483 Cypress 3.4483 Gum 3.4483 Hackberry 3.4483 Hard Maple 3.4483 Hickory 3.4483 Pecan 3.4483 Poplan 3.4483 Red Alder 3.4483 Red Elm 3.4483 Red Oak 6.8966 Sassafras 3.4483 Soft Maple 3.4483 Sycamore 3.4483 White Oak 10.3448 Willow 3.4483 Yellow Birch 3.4483 Hint This problem has huge input, use scanf instead of cin to avoid time limit exceeded. Source Waterloo Local 2002.01.26 考察點是tire樹，但是這題確是非常容易出錯因為看他給的的樣例就會給人一種錯覺，認為字符在A到Z a到z 空格之間，其實題目並沒有這麼說，樹木的名稱可能有其他字符 ，認識到這一點就能過了這題目. [cpp] #include <stdio.h> #include <string.h> #include <stdlib.h> char s1[50]; struct tire { int tag; struct tire* next[300]; }; struct num { char s1[50]; int sum; }a[1000010]; int top; int cmp(const void *e,const void *f) { struct num *p1,*p2; p1=(struct num *)e; p2=(struct num *)f; if(strcmp(p1->s1,p2->s1)>0) { return 1; }else { return -1; } } int main() { struct tire* newnode(); int build(char s2[50],struct tire* p); int i,j,n,m,t; double s; struct tire *head; head=newnode(); top=0; s=0; while(gets(s1)) { t=build(s1,head); s++; if(t==-1) { a[top].sum=1; strcpy(a[top].s1,s1); top++; }else { a[t].sum++; } } qsort(a,top,sizeof(a[0]),cmp); for(i=0;i<=top-1;i++) { printf("%s ",a[i].s1); printf("%.4lf\n",a[i].sum*100/s); } return 0; } struct tire* newnode() { int i; struct tire *p=(struct tire*)malloc(sizeof(struct tire)); p->tag=-1; for(i=0;i<=299;i++) { p->next[i]=NULL; } return p; } int build(char s2[50],struct tire* p) { int i,l=strlen(s2),s; for(i=0;i<=l-1;i++) { www.2cto.com s=s2[i]; if(p->next[s]==NULL) { p->next[s]=newnode(); } p=p->next[s]; } if(p->tag==-1) { p->tag=top; return -1; } return p->tag; }
