Problem Description 讀入兩個小於100的正整數A和B,計算A+B. 需要注意的是:A和B的每一位數字由對應的英文單詞給出. Input 測試輸入包含若干測試用例,每個測試用例占一行,格式為"A + B =",相鄰兩字符串有一個空格間隔.當A和B同時為0時輸入結束,相應的結果不要輸出. Output 對每個測試用例輸出1行,即A+B的值. Sample Input one + two = three four + five six = zero seven + eight nine = zero + zero = Sample Output 3 90 96 [cpp] #include <iostream> #include <cstdio> #include <string.h> using namespace std; char num[10][10] = {"zero","one","two","three","four","five","six","seven","eight","nine"}; int search(char ch[]) { int i; for(i = 0;i<10;i++) { if(!strcmp(ch,num[i])) break; } return i; } int main() { char count[10]; int a,b; while(1) { a = 0; while(scanf("%s",count) && strcmp(count,"+")) { a = a*10+search(count); } b = 0; while(scanf("%s",count) && strcmp(count,"=")) { b = b*10+search(count); } if(a == 0 && b == 0) return 0; else cout << a+b << endl; } return 0; }
