Problem Description
Conversion between the metric and English measurement systems is relatively simple. Often, it involves either multiplying or dividing by a constant. You must write a program that converts between the following units:
Input
The first line of input contains a single integer N, (1 ≤ N ≤ 1000) which is the number of datasets that follow.
Each dataset consists of a single line of input containing a floating point (double precision) number, a space and the unit specification for the measurement to be converted. The unit specification is one of kg, lb, l, or g referring to kilograms, pounds, liters and gallons respectively.
Output
For each dataset, you should generate one line of output with the following values: The dataset number as a decimal integer (start counting at one), a space, and the appropriately converted value rounded to 4 decimal places, a space and the unit specification for the converted value.
Sample Input
5
1 kg
2 l
7 lb
3.5 g
0 l
Sample Output
1 2.2046 lb
2 0.5284 g
3 3.1752 kg
4 13.2489 l
5 0.0000 g
每天必水
[cpp]
#include <stdio.h>
#include <string.h>
int main()
{
int t;
double n,m;
char str[20];
scanf("%d",&t);
for(int i = 1;i<=t;i++)
{
scanf("%lf %s",&n,str);
if(!strcmp(str,"kg"))
{
m = n*2.2046;
printf("%d %.4lf lb\n",i,m);
}
else if(!strcmp(str,"g"))
{
m = n*3.7854;
printf("%d %.4lf l\n",i,m);
}
else if(!strcmp(str,"lb"))
{
m = n*0.4536;
printf("%d %.4lf kg\n",i,m);
}
else if(!strcmp(str,"l"))
{
m = n*0.2642;
printf("%d %.4lf g\n",i,m);
}
}
return 0;
}
#include <stdio.h>
#include <string.h>
int main()
{
int t;
double n,m;
char str[20];
scanf("%d",&t);
for(int i = 1;i<=t;i++)
{
scanf("%lf %s",&n,str);
if(!strcmp(str,"kg"))
{
m = n*2.2046;
printf("%d %.4lf lb\n",i,m);
}
else if(!strcmp(str,"g"))
{
m = n*3.7854;
printf("%d %.4lf l\n",i,m);
}
else if(!strcmp(str,"lb"))
{
m = n*0.4536;
printf("%d %.4lf kg\n",i,m);
}
else if(!strcmp(str,"l"))
{
m = n*0.2642;
printf("%d %.4lf g\n",i,m);
}
}
return 0;
}
