[cpp]
class Solution {
//more detail refer to: http://fisherlei.blogspot.com/2012/12/leetcode-median-of-two-sorted-arrays.html
//using the method of getting the kth number in the two sorted array to solve the median problem
//divide-and-conquer
//very clean and concise
public:
double findMedianSortedArrays(int A[], int m, int B[], int n) {
if((n+m)%2 ==0)
{
return (GetMedian(A,m,B,n, (m+n)/2) + GetMedian(A,m,B,n, (m+n)/2+1))/2.0;
}
else
return GetMedian(A,m,B,n, (m+n)/2+1);
}
int GetMedian(int a[], int n, int b[], int m, int k)//get the kth number in the two sorted array
{
//assert(a && b);
if (n <= 0) return b[k-1];
if (m <= 0) return a[k-1];
if (k <= 1) return min(a[0], b[0]);
//a: section1 section2
//b: section3 section4
if (b[m/2] >= a[n/2])
{
if ((n/2 + 1 + m/2) >= k)
return GetMedian(a, n, b, m/2, k);//abort section 4
else
return GetMedian(a + n/2 + 1, n - (n/2 + 1), b, m, k - (n/2 + 1)); //abort section 1
}
else
{
if ((m/2 + 1 + n/2) >= k)
return GetMedian( a, n/2,b, m, k);//abort section 2
else
return GetMedian( a, n, b + m/2 + 1, m - (m/2 + 1),k - (m/2 + 1));//abort section 3
}
}
};