Given a binary tree, flatten it to a linked list in-place. For example, Given 1 / \ 2 5 / \ \ 3 4 6 The flattened tree should look like: 1 \ 2 \ 3 \ 4 \ 5 \ 6 Hints: If you notice carefully in the flattened tree, each node's right child points to the next node of a pre-order traversal.
void flatten(TreeNode *root) { // Start typing your C/C++ solution below // DO NOT write int main() function if(root==NULL) return; if(root->left == NULL && root->right == NULL) return; flatten(root->left); flatten(root->right); TreeNode* tmpright = root->right; root->right = root->left; root->left = NULL; TreeNode* tmp = root; while(tmp->right) tmp = tmp->right; tmp->right = tmpright; return; }