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Given a linked list, determine if it has a cycle in it.
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Can you solve it without using extra space?
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(M) Linked List Cycle II
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ //思路首先:如果有環?遍歷鏈表將無法走完,如果無環終會走到尾為NULL的位置 //讓一個指針每次走一個,一個指針每次走兩個位置,如果其中一個為NULL則無環,如果相遇了 //則有環 class Solution { public: bool hasCycle(ListNode *head) { if(head==NULL) return false; ListNode *showNode=head; ListNode *fastNode=head; while(true) { if(showNode->next!=NULL) showNode=showNode->next; else return false; if(fastNode->next!=NULL && fastNode->next->next!=NULL) fastNode=fastNode->next->next; else return false; if(showNode==fastNode) return true; } return false; } };