Digital Square
Time Limit : 2000/1000ms (Java/Other) Memory Limit : 32768/32768K (Java/Other)
Total Submission(s) : 10 Accepted Submission(s) : 6
Problem Description Given an integer N,you should come up with the minimum
nonnegative integer M.M meets the follow condition: M
2%10
x=N (x=0,1,2,3....)
Input The first line has an integer T( T< = 1000), the number of test cases. For each case, each line contains one integer N(0<= N <=10[sup]9[/sup]), indicating the given number.
Output For each case output the answer if it exists, otherwise print “None”.
Sample Input
3
3
21
25
Sample Output
None
11
5
Source 2012 Multi-University Training Contest 10
簡單搜索題,判斷幾位數相乘後對余數沒有影響就好
#include
#include
#include
#include
using namespace std;
int t,n;
long long Mod;
struct node
{
long long num;
long long ten;
friend bool operator < (node a,node b)
{
return a.num>b.num;
}
} a,b;
void bfs()
{
priority_queueq;
int num=n%10;
for(int i=0; i<10; i++)
if(i*i%10==num)
{
a.num=i;
a.ten=10;
q.push(a);
}
while(q.size())
{
a=q.top();
if(a.num*a.num%Mod==n)
{
cout<>n;
int nn=n;
Mod=1;
while(nn)
{
Mod*=10;
nn/=10;
}
bfs();
}
}