Find all possible combinations of k numbers that add up to a number n, given that only numbers from 1 to 9 can be used and each combination should be a unique set of numbers.
Ensure that numbers within the set are sorted in ascending order.
Example 1:
Input: k = 3, n = 7
Output:
[[1,2,4]]
Example 2:
Input: k = 3, n = 9
Output:
[[1,2,6], [1,3,5], [2,3,4]]
Solution:
DFS, two conditions for basic case, one is sum , second is k number
public List> combinationSum3(int k, int n) { List
> result = new ArrayList<>(); List
cur = new ArrayList<>(); if(k<1 || n<1 || k>n) return result; dfs(result, cur, 0, k, n, 1); return result; } public void dfs(List > result, List
cur, int sum, int k, int n, int level) { if(sum == n && k==0) { result.add(new ArrayList(cur)); return; } else if(sum> n || k<0) return; for(int i=level;i<=9;i++){ cur.add(i); dfs(result, cur, sum+i, k-1, n, i+1); cur.remove(cur.size()-1); } }