POJ 3164Command Network && UVA 11183 Teen Girl Squad 最小樹形圖

最小樹形圖：簡單來說，求一個圖的G0的最小樹形圖，先求出最短弧集合E0。若E0不存在，則圖G0的最小樹形圖不存在。若存在且不含有向環，則E0就是T0中的所有的邊。如果E0存在且含有有向環，則收縮有向環為一個點u，並形成圖G1，繼續且G1的最小樹形圖直至圖Gi，若圖Gi無最小樹形圖，則圖G0也不存在最小樹形圖，若Gi有最小樹形圖Ti.則逐層展開得到T0

UVA 11183 Teen Girl Squad
Input: Standard Input
Output: Standard Output

– 3 spring rolls please.
– MSG’D!!
– Oh! My stomach lining!
Strong Bad
You are part of a group of n teenage girls armed with cellphones. You have some news you want to tell everyone in the group. The problem is that no two of you are in the same room, and you must communicate using only cellphones. What’s worse is that due to excessive usage, your parents have refused to pay your cellphone bills, so you must distribute the news by calling each other in the cheapest possible way. You will call several of your friends, they will call some of their friends, and so on until everyone in the group hears the news.
Each of you is using a different phone service provider, and you know the price of girl A calling girl B for all possible A and B. Not all of your friends like each other, and some of them will never call people they don’t like. Your job is to find the cheapest possible sequence of calls so that the news spreads from you to all n-1 other members of the group.
Input
The first line of input gives the number of cases, N (N<150). N test cases follow. Each one starts with two lines containing n (0<= n<=1000) and m (0 <= m <= 40,000) . Girls are numbered from 0 to n-1 , and you are girl 0. The next m lines will each contain 3 integers, u, v and w, meaning that a call from girl u to girl v costs w cents (0 <= w <= 1000) . No other calls are possible because of grudges, rivalries and because they are, like, lame. The input file size is around 1200 KB.

Output
For each test case, output one line containing “Case #x:” followed by the cost of the cheapest method of distributing the news. If there is no solution, print “Possums!” instead.

Sample Input Output for Sample Input
4
2
1
0 1 10
2
1
1 0 10
4
4
0 1 10
0 2 10
1 3 20
2 3 30
4
4
0 1 10
1 2 20
2 0 30
2 3 100
Case #1: 10
Case #2: Possums!
Case #3: 40
Case #4: 130

#include
#include
#include
#include
#include
using namespace std;

const int maxn=1010;
const int INF = 0x3f3f3f3f;
const int maxm =40010;

struct Edge
{
    int u,v,cost;
}edge[maxm];

int pre[maxn],id[maxn],vis[maxn],in[maxn];
int zhuliu(int root,int n,int m,Edge edge[])
{
    int u,v;
    int res=0;
    while(1)
    {
        for(int i=0;i<n;i++) in[i]="INF;" for(int="" i="0;i