Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:
Integers in each row are sorted from left to right.The first integer of each row is greater than the last integer of the previous row.For example,
Consider the following matrix:
[ [1, 3, 5, 7], [10, 11, 16, 20], [23, 30, 34, 50] ]
Given target = 3
, return true
.
兩邊逼近
class Solution { public: bool searchMatrix(vector> &matrix, int target) { int i = 0, j = matrix[0].size()-1; while(i < matrix.size() && j >= 0){ if(matrix[i][j] == target) return true; else if(matrix[i][j] < target) i++; else j--; } return false; } };