Given a linked list, determine if it has a cycle in it.
Follow up:
Can you solve it without using extra space?
利用快慢指針
/** * Definition for singly-linked list. * class ListNode { * int val; * ListNode next; * ListNode(int x) { * val = x; * next = null; * } * } */ public class Solution { public boolean hasCycle(ListNode head) { if(head==null) return false; ListNode slow = head; ListNode fast = head.next; while(slow!=null&&fast!=null&&fast.next!=null){ if(slow ==fast) return true; slow = slow.next; fast = fast.next.next; } return false; } }