C說話完成輸入鏈表中倒數第k個節點。本站提示廣大學習愛好者:(C說話完成輸入鏈表中倒數第k個節點)文章只能為提供參考,不一定能成為您想要的結果。以下是C說話完成輸入鏈表中倒數第k個節點正文
本文實例展現了C++完成輸入鏈表中倒數第k個節點的辦法,分享給年夜家供年夜家參考之用。
運轉本文所述實例可完成輸出一個單向鏈表,輸入該鏈表中倒數第k個節點。
詳細完成辦法以下:
/* * Copyright (c) 2011 alexingcool. All Rights Reserved. */ #include <iostream> using namespace std; int array[] = {5, 7, 6, 9, 11, 10, 8}; const int size = sizeof array / sizeof *array; struct Node { Node(int i = 0, Node *n = NULL) : item(i), next(n) {} int item; Node *next; }; Node* construct(int (&array)[size]) { Node dummy; Node *head = &dummy; for(int i = 0; i < size; i++) { Node *temp = new Node(array[i]); head->next = temp; head = temp; } return dummy.next; } void print(Node *head) { while(head) { cout << head->item << " "; head = head->next; } } Node* findKnode(Node *head, int k) { Node *pKnode = head; if(head == NULL) { cout << "link is null" << endl; return NULL; } while(k--) { if(head == NULL) { cout << "k is bigger than the length of the link" << endl; return NULL; } head = head->next; } while(head) { head = head->next; pKnode = pKnode->next; } return pKnode; } void main() { Node *head = construct(array); cout << "source link: "; print(head); cout << endl; Node *kNode = findKnode(head, 5); if(kNode != NULL) cout << "the knode is: " << kNode->item << endl; }
測試用例以下:
1. NULL Link
head = NULL;
2. normal Link, with normal k
k <= len(head);
3. normal Link, with invalid k
k > len(head)
願望本文所述對年夜家C法式算法設計的進修有所贊助。