C語言--左旋字符串中的K個字符
問題：
3.實現一個函數，可以左旋字符串中的k個字符。
AABCD左旋一個字符得到ABCDA
AABCD左旋兩個字符得到BCDAA
#include<stdio.h>
#include<assert.h>
#include<string.h>
void reserve(char* str, int len)
{
assert(str);
char* start = str;
char* end = str + len - 1;
while (start < end)
{
char tmp = *start;
*start = *end;
*end = tmp;
start++;
end--;
}
}
void reserve1(char* str, int len, int k)
{
reserve(str, len);//dcbaa
assert(str);
char* start = str ;
if (k < len)
{
char* end = str + len - 1 - k;
while (start < end)
{
char tmp = *start;
*start = *end;
*end = tmp;
start++;
end--;
}
}
else
{
printf("輸入的字符串個數太大\n");
}
}
void reserve2(char* str, int len,int s)
{
assert(str);
reserve1(str, len, s);//cdbaa
char* start = str+len-s;
char* end = str + len - 1;
while (start < end)
{
char tmp = *start;
*start = *end;
*end = tmp;
start++;
end--;
}
}
int main(void)
{
char str[] = "aabcd";
int len = strlen(str);
int s;
printf("請輸入要旋轉的字符串個數\n");
scanf_s("%d", &s);
reserve2(str, len, s);
printf("%s", str);
}
