1. 數據庫檢索, 得到某字段下所有值
1 - (NSArray *)selectWithColumName: (NSString *)columName 2 tableName: (NSString *)tableName { 3 if ([self openDatabase] == YES) { 4 5 NSString * selectSQL = [NSString stringWithFormat:@"SELECT %@ FROM %@", columName, tableName]; 6 sqlite3_stmt * stmt = nil; 7 8 int preResult = sqlite3_prepare_v2(_db, [selectSQL UTF8String], -1, &stmt, NULL); 9 10 if (preResult == SQLITE_OK) { 11 NSMutableArray * array = [NSMutableArray array]; 12 13 while (sqlite3_step(stmt) == SQLITE_ROW) { 14 [array addObject:[NSString stringWithUTF8String:(const char *)sqlite3_column_text(stmt, 0)]]; 15 } 16 17 sqlite3_finalize(stmt); 18 return array; 19 } else { 20 NSLog(@"check your sqlQuery"); 21 return nil; 22 } 23 } else { 24 NSLog(@"%@", [self errorWithMessage:@"openDB Failure"]); 25 return nil; 26 } 27 }
2. 通過你存儲的模型以及數據表名得到所有的數據
1 #pragma mark - select DB 2 - (NSArray *)selectAllMembersWithTableName: (NSString *)tableName 3 objectModel:(id)object; { 4 if ([self openDatabase] == YES) { 5 6 NSString * selectSQL = [NSString stringWithFormat:@"SELECT * FROM %@", tableName]; 7 sqlite3_stmt * stmt = nil; 8 9 int preResult = sqlite3_prepare_v2(_db, [selectSQL UTF8String], -1, &stmt, NULL); 10 11 if (preResult == SQLITE_OK) { 12 NSMutableArray * array = [NSMutableArray array]; 13 14 while (sqlite3_step(stmt) == SQLITE_ROW) { 15 16 id model = [[[object class] alloc] init]; 17 for (int i=0; i<sqlite3_column_count(stmt); i++) { 18 [model setValue:[NSString stringWithUTF8String:(const char *)sqlite3_column_text(stmt, i)] forKey:[NSString stringWithUTF8String:(const char *)sqlite3_column_name(stmt, i)]]; 19 } 20 [array addObject:model]; 21 [model release]; 22 } 23 24 sqlite3_finalize(stmt); 25 return array; 26 } else { 27 NSLog(@"check your sqlQuery and Model"); 28 return nil; 29 } 30 } else { 31 NSLog(@"%@", [self errorWithMessage:@"SqlQuery error"]); 32 return nil; 33 } 34 }
3. 通過key:value對應關系的字典為數據庫查詢語句的基礎, 得到需要的值
.h文件定義以及使用提示
#pragma mark selectWithSqlQueryDict /* get value with sql statement you must give columName(dict key) = value(dict value) - all string type. e.g dict = { "name" = "xxdbuser", "age" = "19" }; object: model you want 通過包含有你的約束條件的字典、 通過表名稱、 你所給的模型、 返回包含有若干模型的數組 */ - (NSArray *)selectWithSqlQueryDictionary: (NSDictionary *)sqlQueryDictionary tableName: (NSString *)tableName model: (id)object;
.m 文件實現
1 #pragma mark selectWithSqlQuery 2 - (NSArray *)selectWithSqlQueryDictionary: (NSDictionary *)sqlQueryDictionary 3 tableName: (NSString *)tableName 4 model: (id)object { 5 6 // getAllKeys 7 NSArray * keyArray = sqlQueryDictionary.allKeys; 8 NSString * sqlQuery = [NSString stringWithFormat:@"SELECT * FROM %@ WHERE ", tableName]; 9 10 if ([self openDatabase] == YES) { 11 12 // foreach build sqlQuery 13 for (NSString * key in keyArray) { 14 sqlQuery = [sqlQuery stringByAppendingString:[NSString stringWithFormat:@"%@ = '%@' and ", key, sqlQueryDictionary[key]]]; 15 } 16 sqlQuery = [sqlQuery substringToIndex:[sqlQuery length] - 4]; 17 18 sqlite3_stmt * stmt; 19 20 int result = sqlite3_prepare_v2(_db, [sqlQuery UTF8String], -1, &stmt, NULL); 21 if (result == SQLITE_OK) { 22 NSMutableArray * array = [NSMutableArray array]; 23 24 while (sqlite3_step(stmt) == SQLITE_ROW) { 25 26 id model = [[[object class] alloc] init]; 27 for (int i=0; i<sqlite3_column_count(stmt); i++) { 28 [model setValue:[NSString stringWithUTF8String:(const char *)sqlite3_column_text(stmt, i)] forKey:[NSString stringWithUTF8String:(const char *)sqlite3_column_name(stmt, i)]]; 29 } 30 [array addObject:model]; 31 [model release]; 32 } 33 34 sqlite3_finalize(stmt); 35 return array; 36 } else { 37 NSLog(@"check your sqlQuery"); 38 return nil; 39 } 40 41 } else { 42 NSLog(@"%@", [self errorWithMessage:@"openDB Failure"]); 43 return nil; 44 } 45 }
4. 錯誤信息的輸出
1 #pragma mark - errorMessage 2 - (NSError *)errorWithMessage:(NSString *)message { 3 return [NSError errorWithDomain:@"XXDB" code:sqlite3_errcode(_db) userInfo:[NSDictionary dictionaryWithObject:message forKey:NSLocalizedDescriptionKey]]; 4 }
ok 今天就到這裡。 數據庫是數據持久化最常用的辦法。 一定熟練掌握用戶的各種需求實現的辦法
嗯嗯
db_xxx下的field_yyy字段為日期型字段
select * from db_xxx where substr(date(field_yyy),1,7) = '2012-07';