擲骰子游戲-C語言實現

作者：半點閒
博客：blog.csdn.net/cg_i
郵箱：[email protected]
參考書籍：《C和指針》

引子：

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作業2：

“B. (20 points) Simulated Dice
The casino game Table Crapsis a dice game in which a number of betting options are available depending on
the eventual roll of a pair of dice. Players may bet "for" or"against" certain outcomes in a dizzying array of
combinations with varying odds. Each round of Crapsbegins with an initial roll of the dice (the so-called
'come-out' roll). The player 'wins' on the initial roll if it totals 7 or 11, and 'Craps out'(loses) if the roll is 2, 3
or 12.

Write a simulation program to determine the probability of winning vs. losing on the first roll in the game of
Craps. Your program must include a void function named diceRollthat will use the rand()function to
provide 2 pseudo-random integer values in the range [1..6] representing a single roll of a pair of (independent)
dice.

Your mainprogram must do the following:
? Prompt the user, input an integer seed value and seed the pseudo-random number generator with that
value
? Simulate 10,000 dice rolls using the diceRollfunction and determine the number of 'wins' (7, 11)
and 'losses' (2, 3, 12)
? Display the number of 'wins' and 'losses', and also the resulting probabilities on the terminal display
(note the theoretical probability for 'win' on the first roll is .2222 and for a 'loss' on the first roll is .1111)

Example:
Enter an integer seed value: 1
Number of wins: 2230
Probability of winning: 0.223
Number of losses: 1098
Probability of losing: 0.1098
Enter an integer seed value: 102
Number of wins: 2258
Probability of winning: 0.2258
Number of losses: 1072
Probability of losing: 0.1072

大意是寫一個模擬擲骰子的游戲，每次擲兩個骰子每個骰子是一個正方體有6面上面標有1、2、3、4、5、6個圓點，當骰子停止時將每個骰子朝上的點數相加，如果所得的和為2、3或12那麼游戲者輸掉；和為7、11贏；並模擬1000次擲骼子的結果。”

代碼（作業要求用C++實現，老子沒心情給就給個C的）：

#include 
#include 
#define  ROLLS 1000


void main()
{
	int i = 0;
	int numOfDice1;
	int numOfDice2;
	int sum;
	int status = 0;
	int numOfWin = 0;
	int numOfLose = 0;
	unsigned value = 0;

	printf("Enter an integer seed value:");
	scanf("%u",&value);
	srand(value);

	for(i = 0; i <= ROLLS; i++){
		numOfDice1 = 1 + rand() % 6;
		numOfDice2 = 1 + rand() % 6;
		sum = numOfDice1 + numOfDice2;
		
		switch(sum){
			case 7:
			case 11:
				status = 1;
				numOfWin++;
				break;
			case 2:
			case 3:
			case 12:
				status = 0;
				numOfLose++;
				break;
		}
	}
	printf("Number of winns:%d\n",numOfWin);
	printf("Probability of winning:%.3f\n",(float)numOfWin / ROLLS);
	printf("Number of losses:%d\n",numOfLose);
	printf("Probability of losing:%.3f\n",(float)numOfLose  / ROLLS);
}

結尾：

事由是郁悶了點。但從學習的角度上，我希望各位大蝦能給我上述代碼批評及建議，畢竟我E文太差不知道題目是否理解的對，也望各位給出建議。我也好從中學到些東西，知識本身是可貴的，小弟在此拜謝了！