我的C/C++之路-006課(計算輸入的時間是一年中的第幾天)

當然，這個程序很簡單，呵呵，簡單也做了下

/*
計算輸入的時間是一年中的第幾天
*/
void theDayOfYear()
{
 int nonleapYear[12] = {31,28,31,30,31,30,31,31,30,31,30,31};
 int leapYear[12] = {31,29,31,30,31,30,31,31,30,31,30,31};
 int year,month,day,num=0;
 printf("please input date like:2012 4 24 \n");
 scanf("%d %d %d",&year,&month,&day);
 //判斷是否是閏年
 if((year%4==0&&year%100!=0)||year%400==0)
 {
  for(int i=0;i<month-1;i++)
  {
   num += leapYear[i];
  }
  num += day;
 }
 else
 {
  for(int i=0;i<month-1;i++)
  {
   num += nonleapYear[i];
  }
  num += day;
 }
 printf("the day of year is:%d\n",num);
}