從上圖可以看到，每個綠色格子代表一個20*20像素的障礙物，只能說勉強達到描繪障礙物的效果吧。從而又驗證了我們上一節所講到的GridSize越小，定位將越精確，難道不是至理名言嗎！
有了這個思路，接下來我用了3個循環算法實現了左部分的障礙物設定：
//構建障礙物
for (int y = 12; y <= 27; y++) {
for (int x = 0; x <= 7; x++) {
//障礙物在矩陣中用0表示
Matrix[x, y] = 0;
rect = new Rectangle();
rect.Fill = new SolidColorBrush(Colors.GreenYellow);
rect.Opacity = 0.3;
rect.Stroke = new SolidColorBrush(Colors.Gray);
rect.Width = GridSize;
rect.Height = GridSize;
CarrIEr.Children.Add(rect);
Canvas.SetLeft(rect, x * GridSize);
Canvas.SetTop(rect, y * GridSize);
}
}
int move = 0;
for (int x = 8; x <= 15; x++) {
for (int y = 12; y <= 18; y++) {
Matrix[x, y - move] = 0;
rect = new Rectangle();
rect.Fill = new SolidColorBrush(Colors.GreenYellow);
rect.Opacity = 0.3;
rect.Stroke = new SolidColorBrush(Colors.Gray);
rect.Width = GridSize;
rect.Height = GridSize;
CarrIEr.Children.Add(rect);
Canvas.SetLeft(rect, x * GridSize);
Canvas.SetTop(rect, (y - move) * GridSize);
}
move = x % 2 == 0 ? move + 1 : move;
}
int start_y = 4;
int end_y = 10;
for (int x = 16; x <= 23; x++) {
for (int y = start_y; y <= end_y; y++) {
Matrix[x, y + move] = 0;
rect = new Rectangle();
rect.Fill = new SolidColorBrush(Colors.GreenYellow);
rect.Opacity = 0.3;
rect.Stroke = new SolidColorBrush(Colors.Gray);
rect.Width = GridSize;
rect.Height = GridSize;
CarrIEr.Children.Add(rect);
Canvas.SetLeft(rect, x * GridSize);
Canvas.SetTop(rect, (y + move) * GridSize);
}
start_y = x % 3 == 0 ? start_y + 1 : start_y;
end_y = x % 3 == 0 ? end_y - 1 : end_y;
}
構建好障礙物後運行程序測試的效果如下圖：
