C#模擬MSN窗體抖動
窗體抖動是件很有意思的事情,就讓我們看看一起來看看它的原理吧。
其實是生成隨機數,然後改變Form的左上角的坐標。
我用的是循環來弄得,其實可以用timer來控制.
我把抖動分成了兩種抖動:
1。 生成隨機數,改變窗體左上角坐標,然後立即把窗體的坐上角坐標還原,繼續循環。
2。 生成隨機數,改變窗體左上角坐標,循環完畢之後,然後立即把窗體的坐上角坐標還原。
核心代碼如下:
//第一種抖動
private void button1_Click(object sender, EventArgs e)
{
int recordx = this.Left; //保存原來窗體的左上角的x坐標
int recordy = this.Top; //保存原來窗體的左上角的y坐標
Random random = new Random();
for (int i = 0; i < 100; i++)
{
int x = random.Next(rand);
int y = random.Next(rand);
if (x % 2 == 0)
{
this.Left = this.Left + x;
}
else
{
this.Left = this.Left - x;
}
if (y % 2 == 0)
{
this.Top = this.Top + y;
}
else
{
this.Top = this.Top - y;
}
this.Left = recordx; //還原原始窗體的左上角的x坐標
this.Top = recordy; //還原原始窗體的左上角的y坐標
}
}
//第二種抖動
private void button2_Click(object sender, EventArgs e)
{
int recordx = this.Left;
int recordy = this.Top;
Random random = new Random();
for (int i = 0; i < 50; i++)
{
int x = random.Next(rand);
int y = random.Next(rand);
if (x % 2 == 0)
{
this.Left = this.Left + x;
}
else
{
this.Left = this.Left - x;
}
if (y % 2 == 0)
{
this.Top = this.Top + y;
}
else
{
this.Top = this.Top - y;
}
System.Threading.Thread.Sleep(1);
}
this.Left = recordx;
this.Top = recordy;
}