C#完成盤算年紀的簡略辦法匯總。本站提示廣大學習愛好者:(C#完成盤算年紀的簡略辦法匯總)文章只能為提供參考,不一定能成為您想要的結果。以下是C#完成盤算年紀的簡略辦法匯總正文
vs2010測試經由過程,重要思惟是由出身日期和以後日期,兩個日期盤算出年紀(歲、月、天)
using System; using System.Collections.Generic; using System.Text; namespace PublicClass { public static class CalculationDate { /// <summary> /// 由兩個日期盤算出年紀(歲、月、天) /// </summary> public static void calculationDate(DateTime beginDateTime, DateTime endDateTime) { if (beginDateTime > endDateTime) throw new Exception("開端時光應小於或等與停止時光!"); /*盤算出身日期到以後日期總月數*/ int Months = endDateTime.Month - beginDateTime.Month + 12 * (endDateTime.Year - beginDateTime.Year); /*出身日期加總月數後,假如年夜於以後日期則減一個月*/ int totalMonth = (beginDateTime.AddMonths(Months) > endDateTime) ? Months - 1 : Months; /*盤算全年*/ int fullYear = totalMonth / 12; /*盤算整月*/ int fullMonth = totalMonth % 12; /*盤算天數*/ DateTime changeDate = beginDateTime.AddMonths(totalMonth); double days = (endDateTime - changeDate).TotalDays; } } }
再簡略一些:
public int CalculateAgeCorrect(DateTime birthDate, DateTime now) { int age = now.Year - birthDate.Year; if (now.Month < birthDate.Month || (now.Month == birthDate.Month && now.Day < birthDate.Day)) age--; return age; }
上面我們來看看慣例辦法:
辦法1:
string m_Str = "1984-04-04"; int m_Y1 = DateTime.Parse(m_Str).Year; int m_Y2 = DateTime.Now.Year; int m_Age = m_Y2 - m_Y1; Response.Write(m_Age);
辦法2:
假如你將日期格局化為yyyymmdd,而且從以後日子減去誕辰,最初去除4個數字,就獲得年紀了:)
我信任如許的辦法可以用任何說話完成:
20080814-19800703=280111
去除最初4位 = 28.
int now =int.Parse(DateTime.Today.ToString("yyyyMMdd")); int dob =int.Parse(dateDOB.ToString("yyyyMMdd")); string dif =(now - dob).ToString(); string age ="0"; if(dif.Length>4) age = dif.Substring(0, dif.Length-4);
辦法3:
DateTime now =DateTime.Today; int age = now.Year- bday.Year; if(bday > now.AddYears(-age)) age--;
以上所述就是本文的全體內容了,願望能對年夜家進修C#有所贊助。