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 程式師世界 >> 編程語言 >> .NET網頁編程 >> C# >> C#入門知識 >> C#線程隊列用法實例剖析

C#線程隊列用法實例剖析

編輯:C#入門知識

C#線程隊列用法實例剖析。本站提示廣大學習愛好者:(C#線程隊列用法實例剖析)文章只能為提供參考,不一定能成為您想要的結果。以下是C#線程隊列用法實例剖析正文


本文實例講述了C#線程隊列用法。分享給年夜家供年夜家參考。詳細以下:

using System;
using System.Collections.Generic;
using System.Text;
using System.Threading;
namespace ThreadPro
{
 class Program
 {
  static Mutex gM1;
  static Mutex gM2;
  const int ITERS = 100;
  static AutoResetEvent Event1 = new AutoResetEvent(false);
  static AutoResetEvent Event2 = new AutoResetEvent(false);
  static AutoResetEvent Event3 = new AutoResetEvent(false);
  static AutoResetEvent Event4 = new AutoResetEvent(false);
  static void Main(string[] args)
  {
   Console.WriteLine("Mutex Sample ");
   //創立一個Mutex對象,而且定名為MyMutex
   gM1 = new Mutex(true, "MyMutex");
   //創立一個未定名的Mutex 對象.
   gM2 = new Mutex(true);
   Console.WriteLine(" - Main Owns gM1 and gM2");
   AutoResetEvent[] evs = new AutoResetEvent[4];
   evs[0] = Event1; //為前面的線程t1,t2,t3,t4界說AutoResetEvent對象
   evs[1] = Event2;
   Program tm = new Program();
   Thread t1 = new Thread(new ThreadStart(tm.t1Start));
   Thread t2 = new Thread(new ThreadStart(tm.t2Start));
   Thread t3 = new Thread(new ThreadStart(tm.t3Start));
   Thread t4 = new Thread(new ThreadStart(tm.t4Start));
   t1.Start();// 應用Mutex.WaitAll()辦法期待一個Mutex數組中的對象全體被釋放
   t2.Start();// 應用Mutex.WaitOne()辦法期待gM1的釋放
   t3.Start();// 應用Mutex.WaitAny()辦法期待一個Mutex數組中隨意率性一個對象被釋放
   t4.Start();// 應用Mutex.WaitOne()辦法期待gM2的釋放
   Thread.Sleep(2000);
   Console.WriteLine(" - Main releases gM1");
   gM1.ReleaseMutex(); //線程t2,t3停止前提滿
   Thread.Sleep(1000);
   Console.WriteLine(" - Main releases gM2");
   gM2.ReleaseMutex(); //線程t1,t4停止前提知足
   //期待一切四個線程停止
   WaitHandle.WaitAll(evs);
   Console.WriteLine(" Mutex Sample");
   Console.ReadLine();
  }
  public void t1Start()
  {
   Console.WriteLine("辦法一運轉, Mutex.WaitAll(Mutex[])");
   Mutex[] gMs = new Mutex[2];
   gMs[0] = gM1;//創立一個Mutex數組作為Mutex.WaitAll()辦法的參數
   gMs[1] = gM2;
   Mutex.WaitAll(gMs);//期待gM1和gM2都被釋放
   gM1.ReleaseMutex(); //修改上一次湧現的毛病
   gM2.ReleaseMutex(); //修改上一次湧現的毛病
   Thread.Sleep(2000);
   Console.WriteLine("辦法一終了,WaitAll(Mutex[]) satisfied");
   Event1.Set(); //線程停止,將Event1設置為有旌旗燈號狀況
  }
  public void t2Start()
  {
   Console.WriteLine("辦法二運轉, gM1.WaitOne( )");
   gM1.WaitOne();//期待gM1的釋放
   gM1.ReleaseMutex(); //修改上一次湧現的毛病
   Console.WriteLine("辦法二終了, gM1.WaitOne( ) satisfied");
   Event2.Set();//線程停止,將Event2設置為有旌旗燈號狀況
  }
  public void t3Start()
  {
   Console.WriteLine("t3Start started, Mutex.WaitAny(Mutex[])");
   Mutex[] gMs = new Mutex[2];
   gMs[0] = gM1;//創立一個Mutex數組作為Mutex.WaitAny()辦法的參數
   gMs[1] = gM2;
   Mutex.WaitAny(gMs);//期待數組中隨意率性一個Mutex對象被釋放
   gM1.ReleaseMutex(); //修改上一次湧現的毛病
   Console.WriteLine("t3Start finished, Mutex.WaitAny(Mutex[])");
   Event3.Set();//線程停止,將Event3設置為有旌旗燈號狀況
  }
  public void t4Start()
  {
   Console.WriteLine("t4Start started, gM2.WaitOne( )");
   gM2.WaitOne();//期待gM2被釋放
   gM2.ReleaseMutex(); //修改上一次湧現的毛病
   Console.WriteLine("t4Start finished, gM2.WaitOne( )");
   Event4.Set();//線程停止,將Event4設置為有旌旗燈號狀況
  }
 }
}

願望本文所述對年夜家的C#法式設計有所贊助。

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